Asquare is inscribed in a circle. if the area of the square is 9 in2, what is the ratio of the circumference of the circle to the area of the circle?

First you have to find the diagonal of the square ( that will be the diameter) each side has to be 3 in since the it is a square( every Side is equal) if you cut the square in half you will get a isosceles right triangle, the sides in the triangle is x x and the x(sqroot2 ) since we have sides of 3 that means that the diagonal is 3 * sqroot2, The circumference is 3 *sqroot2*pi
The area is ((3*sqroot2)/2)^2 so the answer is (3 *sqroot2*pi):(((3*sqroot2)/2)^2)

X=y+4 is the answe