What is the circumference of a circle that circumscribes a triangle with side lengths of 3, 4, and 5?

Circumference of the circle = 15.70 units.

Step-by-step explanation:

In this question three sides of a triangle has been given as 3, 4 and 5 units.

These are the sides of a right angle triangle.

3² + 4² = 5² [By Pythagoras theorem]

9 + 16 = 25

If this triangle is inscribed in a circle then Hypotenuse of the triangle will be the diameter of the circle.

Theorem for the angle formed in the semicircle says, "angle formed by drawing the the lines from the ends of the diameter of a circle to it's circumference form a right angle."

Therefore, radius of the circle will be units

Now we know the formula of circumference of the circle = 2πr

= 2π(2.5)

= 2(3.14)(2.5)

= 15.70 units

mk./km: lm

step-by-step explanation:

,mlmlm

; mk

lk