With this question it's really hard

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

8litres of paint can cover 129.6 m². how much paint is required to paint an area of 243m²?

Apolynomial has two terms. check all of the factoring methods that should be considered. common factor difference of cubes sum of cubes difference of squares perfect-square trinomial factoring by grouping