∠ace is formed by two secants intersecting outside of a circle. if minor arc bd = 28°, minor arc ab = 112°, and minor arc de = 112°, what is the measure of ∠ace?

∠ACE = 40°

Step-by-step explanation:

Refer the attached figure .

Since we know that sum of measures of all arcs is 360°

arc AE + arc AB +arc BD +arc DE = 360°

arc AE+ 252°=360°

arc AE=360°

-252°

arc AE=108°

Now to find the ∠ACE , we will use the theorem.

Theorem : If two secants intersect to form the vertex of an angle outside a circle and the sides of the angle intercept arcs on the circle,then the measure of the angle is equal to one-half the difference of the measures of the arcs intercepted by the sides of the angle.

For∠ACE

The arcs intercepted by the sides of the angle.: arc AE =108° and arc BD=28°

So, by theorem :

Hence the measure of ∠ACE is 40°

3201

step-by-step explanation:

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: