In simplest a+bi form, the roots of the equations x^2=6x-10 are?

I hope this helps you

x^2-6x+9= -1

(x-3)^2= -1

(x-3)^2=i^2

x-3=i

x=3+i

x=3-i

or we can find disctirminant

x^2-6x+10=0

a=1

b= -6

c=10

disctirminant=b^2-4ac

disctirminant=(-6)^2-4.1.10

disctirminant=36-40

disctirminant= -4

i^2= -1

x1,2= -b (+,-) square root of disctirminant /2a

x1= -(-6)+square root of -4/2.1

x1=6+2i/2=3+i

x2= -(-6)-square root of -4/2.1

x2=6-2i/2=3-i

In this problem it decreased 20%