![\bf 2x+\sqrt{4x^2}+\sqrt[3]{8x^3}\qquad \begin{cases} 4\to 2^2\\ 8\to 2^3 \end{cases}\qquad thus \\\\\\ 2x+\sqrt{2^2x^2}+\sqrt[3]{2^3x^3}\implies 2x+\sqrt{(2x)^2}+\sqrt[3]{(2x)^3} \\\\\\ 2x+2x+2x=\boxed{6x}](/tpl/images/0275/7130/03363.png)
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