Find the sum of the sequence. 45+46+47+48++108

We know, S = n/2 [ a + l ]
Here, a = 45
l = 108

Calculation of n:
a(n) = a + (n - 1)d
108 = 45 + (n - 1)1
108 - 45 = n - 1
63 + 1 = n
n = 64

Now, substitute in the expression:
S = 64/2 [ 45 + 108 ]
S = 32 [ 153 ]
S = 4896

In short, Your Answer would be 4896

Hope this helps!

The Total sum of the mentioned series is 4896