What are the zeros of the function?
f(t)=t^2-13t+36

the zeros of the function are: 9 and 4

Step-by-step explanation:

Given the function:

To find the  zeros of the function:

Set f(t) = 0

then;

Split the middle term as: -9 and -4 we have;

⇒

Take (t-9) common we have;

By zero product property we have;

t-9 = 0 and t-4 = 0

⇒t = 9 and t = 4

Therefore, the zeros of the function are: 9 and 4

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

try soting them out first

step-by-step explanation: