Abaseball team’s roster consists of 25 players with 13 position players and the rest being pitchers. the team’s batting order for a particular game consists of 9 players. the first 8 places in the batting order are taken by position players. the last place is taken by a pitcher. how many batting orders are possible? use the formula for permutations to find your answer. a.15,444 b.2,042,975 c.51,891,840 d.622,702,080

d.622,702,080

Step-by-step explanation:

Given: The total number of players in a baseball team= 25

The number of position player= 13

The number of pitchers= 25-13=12

Since,  team’s batting order for a particular game consists of 9 players.

And the 8 places in the batting order are taken by position players and last place is taken by a pitcher.

So by permutations, the number of batting orders

Hence, there are 622,702,080 batting orders possible.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x