which counterexample proves this statement is false?
since y = |x| is a function, x = |y| is...
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Mathematics, 24.08.2019 02:30, sonyfan
which counterexample proves this statement is false?
since y = |x| is a function, x = |y| is also a function.
a)
consider x = |y|, for a value of x > 0, there are two y-values.
b)
consider y = |x|, for any x there is exactly one absolute value.
c)
consider y = |x|, for a value of x < 0, there are two y-values.
d)
consider x = |y|, for a value of x > 0, there are two x-values.
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