In the figure below,
pt = x + 2
tr = y
qt = 2x
and ts = y + 3

(picture attached below)

find the values of x and y in parallelogram pqrs.

a. x = 2, y = 1
b. x = 1, y = 3
c. x = 4, y = 5
d. x = 5, y = 7

in advance! : )

Option D is correct

x = 5 , y = 7

Step-by-step explanation:

Properties of parallelogram:

Diagonal bisects each other.

In other way, we can say that the diagonal intersects each other at half-way point.

As per the given statement:

PT = x + 2

TR = y

QT = 2x   and TS = y + 3

From the given figure:

In parallelogram PQRS:

By properties we have;

PT = TR

QT = TS

Substitute the given values we have;

             .....[1]

          .....[2]

Substitute equation [1] into [2] we have;

⇒2x = x+5

Subtract x from both sides we have;

x = 5

Substitute x = 5 in [1] we have;

5+2 = y

7 = y

or

y= 7

Therefore, the value of x and y are:

x = 5 , y = 7

1 ?

step-by-step explanation:

u said 1+1+1+1+1+1+1+1+1+1+1+1*0 so ur adding 1 but then multiplying by 0 so its 0 but then u said 1*0+1 so now ur adding 1 so the answer is juan ?

~leah