The line with equation x−y=0 coincides with the terminal side of an angle θ in standard position in quadrant iii .

what is the value of tanθ

value of tanθ = 1

Step-by-step explanation:

Given the line of the equation: x -y = 0

We can write this as;

y = x.

In Quadrant III, value of tangent is positive i.e,

We know the equation of line is given by : y=mx+b where m is the slope of line and b is the y-intercept.

On comparing with the given equation:

m =1 , b = 0

Since, slope(m) = 1

Using Slope(m) =

therefore, the value of tanθ = 1

e) none of the above because the measure of angle cba is 101°

5x+10 is the correct one

hope this