Two spherical balloons are filled with water. the first balloon has a radius of 3 cm, and the second has a radius of 6 cm. how much greater is the volume of water in the larger balloon than in the smaller balloon? use 3.14 to approximate pi. round to the nearest hundredth if necessary. enter your answer in the box.

The answer is 791.28 cm³ ≈ 791.3 cm³

To calculate this we need to calculate the volume of each balloon.
The volume of a sphere with radius r is:
V = 4/3 π r³

Balloon 1:
r1 = 3 cm
V1 = 4/3 * 3.14 * 3³
V1 = 113.04 cm³

Balloon 2:
r2 = 6 cm
V2 = 4/3 * 3.14 * 6³
V2 = 904.32 cm³

How much more water is in the larger balloon than in the smaller balloon:
V2 - V1 = 904.32 cm³ - 113.04 cm³
             = 791.28 cm³
             ≈ 791.3 cm³

12+3b -1=-5-b -12-1+5=-b-3b -8=-4b