Which shows one way to determine the factors of x^3 + 4x2 + 5x +20 by grouping?
a. x(x^2+4) + 5(x^2+4)
b. x^2(x+4) +5(x+4)
c. x^2(x+5) +4(x+5)
d. x(x^2+5) + 4x(x^2+5)

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !