Which could be the resulting equation when elimination is used to solve the given system of equations?
5a+5b=25
-5a+5b=35

Hence, we get the equation on elimination as:

10b=60

( Also a= -1 and b=6)

Step-by-step explanation:

We have to use the elimination method to solve the following system of equation with variables a and b:

5a+5b=25 (1)

-5a+5b=35(2)

Clearly on adding equation (1) to (2) we get:

      5a+5b=25

     -5a+5b=35

     0+10b=60

i.e. 10b=60 is the equation that we obtain and on solving this we obtain:

b=6 ( since on dividing both side of the equality by 10)

Also, on putting value of b in equation (1) we obtain the value of a as:

5a+5×6=25

5a+30=25

5a=25-30

5a=-5

Hence, a= -1.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

idk

step-by-step explanation: