Suppose that a company claims that its coffee cans contain 8.2 ounces of coffee, on average. you take many large samples, and find, each time, that the mean weight of the sample is within the 95% confidence interval. which of the following would be a reasonable conclusion?

Accept the claim that mean = 8.2oz.

Step-by-step explanation:

Given that a company claims that its coffee cans contain 8.2 ounces of coffee, on average.

To check this, normally large samples are drawn and sample mean is calculated

Then hypotheses created as

H0: Mean = 8.2

Ha: Mean not equals 8.2

The std deviation of sample is found out and then 95% confidence interval is calculated.

If the sample mean falls within 95% confidence interval, then we are 95% confident that for large samples, the sample mean would fall within this interval. Also the claim can be accepted.

Hence conclusion is accept null hypothesis that mean = 8.2 oz.

The company's coffee cans contain 8.2 ounces of coffee, on average.

Step-by-step explanation:

4038

step-by-step explanation:

pleaze mark brainliest!

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3