Express answer in exact form.

given a circle with an 8" radius, find the area of the smaller segment whose chord is 8" long

I'm guessing that you want to find the segment area of a circle that has a radius AO = 8" and a chord AB with a length of 8".

Sine angle AOD = AE / OA
Sine angle AOD = 4 / 8
Sine angle AOD = .5
arc sine (.5) = 30 degrees
So, angle AOB = 60 degrees

Circle Area = PI * radius^2
Circle Area = 201.06
Sector Area = (60/360) * 201.06
Sector Area = 33.51

Line OE^2 =  AO^2 -AE^2
Line OE^2 =  64 -16
Line OE = 6.9282032303

Triangle AOB Area = OE*AE =  6.9282032303 * 4
Triangle AOB Area =  27.7128129211

Segment Area = Sector Area -Triangle AOB Area
Segment Area = 33.51 -27.71
Segment Area = 5.80

I’m pretty sure the * means multiplication. so, if you multiply 5*1, it would equal 5. they are basically are-writing 5x1 as 5*1. so they would be… 5 10152025303540455055