Two equations are given below:
a - 3b = 16
a = b - 2
what is the solution to the set of problems in the form (a, b)?
a. (-2, -6)
b. (-7, -9)
c. (-11, -9)
d. (-12, -10)

You can solve this question by equating the two linear systems (by "substitution" or "elimination")

By substitution
-Take Equation 2 and substitute it in Equation 1
you will have (b-2) - 3b= 16 => -2b=18 => b=-9
-Then, take b=-9 and substitute it in one of the equations( it doesn't really matter )
For eg substituting in equation 2 yields a=-11

Final ans: C where (a,b) is (-11,-9)