Find the surface area round to nearest tenth if necessary
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Answers: 1
Mathematics, 20.06.2019 18:04, Uc34758
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?
Answers: 2
Mathematics, 21.06.2019 17:30, anonymous1813
Using the side-splitter theorem, daniel wrote a proportion for the segment formed by luke segment de. what is ec?
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Mathematics, 21.06.2019 18:00, Tellyy8104
On a piece of paper, graph y< x+1. then determine which answer matches the graph you drew.
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