Cylinder a has a radius of 4 inches and a height of 2 inches. cylinder b has a radius of 2 inches. what is the height of cylinder b to the nearest inch if both cylinders have the same volume?

h=8 in

Step-by-step explanation:

Formula: V=pi r^2 h

Cylinder A:

radius: 4 in  height: 2 in

V=pi*4^*2*2

V=pi*16*2

V=pi*32

V=3.14*32

V=100.48

Cylinder B:

radius: 2 in  height: ?  volume: 100.48

100.48=pi*2^2*h

100.48=pi*4*h

100.48=3.14*4*h

100.48=12.56*h

100.48/12.56=h

h=8 in

Hope this helps :)

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

the answer is a

step-by-step explanation: