The diagram shows a cone and its axis of rotation. if a plane passes through the axis of rotation, which type of cross section will be formed?

1. a circle
2. an isosceles triangle
3. a parabola
4. an oval

2) an isosceles triangle

Step-by-step explanation:

Given that the diagram shows a cone and its axis of rotation.

A plane passes through the axis of rotation,

Then the image formed would be an isosceles triangle.

It cannot be a circle because only if plane passes perpendicular to axis of rotation circle will be formed

If plane is parallel to axis of rotation then parabola would be formed

If a plane making an angle not 90 cuts axis of rotation then an oval would be formed

So correct answer is option 2)

an isosceles triangle

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.