![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](/tpl/images/0175/9691/0e2bd.png)
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
is always positive for 
. That means at ![[-2,1]](/tpl/images/0175/9691/cf9ae.png)
.
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Ex 2.8
3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1...
Mathematics, 18.08.2019 11:50, davisdarby2
Ex 2.8
3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1
Answers: 1
Other questions on the subject: Mathematics
Mathematics, 21.06.2019 17:30, mduncan840
The marriott family bought a new apartment three years ago for $65,000. the apartment is now worth $86,515. assuming a steady rate of growth, what was the yearly rate of appreciation? what is the percent of the yearly rate of appreciation?
Answers: 1
Mathematics, 21.06.2019 22:00, huangjianhe135
The difference of two numbers is 40. find the numbers if 0.3 parts of one number is equal to 37.5% of the other one.
Answers: 1
Mathematics, 21.06.2019 22:00, Morehollie9428
Type the correct answer in the box. consider the system of linear equations below. rewrite one of the two equations above in the form ax + by = c, where a, b, and c are constants, so that the sum of the new equation and the unchanged equation from the original system results in an equation in one variable.
Answers: 2
Do you know the correct answer?
Questions in other subjects:
History, 11.07.2019 15:30
Mathematics, 11.07.2019 15:30
Chemistry, 11.07.2019 15:30
Social Studies, 11.07.2019 15:30
