Abasketball with a radius of 24.1 cm rolls 8.0m in 11 seconds. what is the angular frequency of the ball?

The formula for angular frequency is:

ω = velocity/radius

Since we are given distance(8.0m) and time(11 seconds) , we can also express the formula as:

ω = distance/(radius)(time)

Substituting the given values:

8.0m/(0.241m)(11s)

Which would give us the answer of 3.03 seconds.

Hope this answer helps.

good luck