![x= \sqrt[8]{y} \\ y = z^{16} ](/tpl/images/0473/4627/73d3e.png)
![x = \sqrt[8]{z^{16}} = (z^{16})^{1/8} = z^{16/8} = z^2](/tpl/images/0473/4627/70dac.png)
If x= eighth root of y and y= z^16 how is x proportionate to z ?
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Mathematics, 27.01.2020 21:31, homer57idkiminatest
If x= eighth root of y and y= z^16 how is x proportionate to z ?
Answers: 1
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