What is the equation of the circle that has a diameter with the end points located at (-5,-3) and (-11,-3)
a. (x-8)^2 + (y-3)^2=9
b. (x+5)^2+(y+3)^2=9
c. (x+8)^2+(y+3)^2=9
d. (x+8)^2+(y+3)^2=36

First find the radius which is half of the distance between the endpoints

r =  0.5 * ( 11-5) =  3

and the x coordinate of the center of the circle is  ( -11--5) / 2 =  -8
so center is at (-8,-3)

as equation of circle is (x -a)^2 + (y - b)^2 = r^2   where (a,b) = center

our circle will have the equation

(x + 8)^2 + (x + 3)^2 = 9

One unique triangle, because those angles add up to 180, and that's how many degrees there are in one triangle.

Istg idk..if there all the same length there all the same number but use google