Two vertices of a right triangle have coordinates (6, −2) and (1, 6) .

select each ordered pair that could be the coordinates of the third vertex.

(6, 6)

(1, −2)

(1, 1)

(−2, 1)

ANSWER

The coordinates of the third vertices are or .

EXPLANATION

Let the hypotenuse of the right angle triangle have vertices and .

The third point is the intersection of the horizontal line that passes through (6,-2), that has equation and the vertical line that passes through which also has equation .

Hence one possible coordinates of the third vertex is .

The third vertex could also be the intersection of the vertical line that passes through (6,-2), that has equation and the horizontal line that passes through which also has equation .

Hence another possible coordinates of the third vertex is .

See diagram in attachment

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: