﻿ (1+x^2)dy/dx+2xy-4x^2=0 bu using bernoulli's equation  , 18.10.2019 06:30, lee1817

# (1+x^2)dy/dx+2xy-4x^2=0 bu using bernoulli's equation ### Other questions on the subject: Mathematics Mathematics, 21.06.2019 13:30, janeliles
Lassify the function as linear or quadratic and identify the quadratic, linear, and constant terms. f(x) = (3x + 2)(−6x − 3) linear function; linear term: −21x; constant term: −6 linear function; linear term: −18x2; constant term: −6 quadratic function; quadratic term: 6x2; linear term: 24x; constant term: −6 quadratic function; quadratic term: −18x2; linear term: −21x; constant term: −6 Mathematics, 21.06.2019 18:00, HTTYD
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Anumber cube is rolled two times in a row. find the probability it will land on 2 on the first roll and a number greater then 4 on the second roll
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(1+x^2)dy/dx+2xy-4x^2=0 bu using bernoulli's equation...

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