Solve (x + 3)^2 + (x + 3) β 2 = 0.
let u = x+3
rewrite the equation in terms of u.
...
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Mathematics, 06.10.2019 16:00, nanda22
Solve (x + 3)^2 + (x + 3) β 2 = 0.
let u = x+3
rewrite the equation in terms of u.
a. u^2 + u β 2 = 0
b. (u^2 + 9) + u β 2 = 0
c. u^2 + u + 1 = 0
![answer](/tpl/images/cats/otvet.png)
Answers: 3
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Mathematics, 22.06.2019 00:00, Lions8457
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