Start at 12. create a pattern that multiplies each number by 4. stop when you have 5 numbers

Well, I think this is much better viewed in python:
#Start at 12. Create a pattern that multiplies each number by 4. Stop when you have 5 numbers
req_list = [12]i = 1while i < 5:    for b in req_list:        b = b * 4    i += 1    req_list.append(b)print(req_list)    

4+2=-2. 1+2=3. y=-2/3x+b. 2=4/3+b. 2/3=b. the answer is y= -2/3x+2/3