Nichole tried to evaluate (-z)3 where (-z) = -3.
(-z)3
a) =(β(β3))3
b) =(...
Mathematics, 05.01.2020 07:31, lillymt1023
Nichole tried to evaluate (-z)3 where (-z) = -3.
(-z)3
a) =(β(β3))3
b) =(3)3
c) =27
find nichole's mistake
*p. s this is coming from khan academy, the lesson is equations with square roots & cube roots and it is my last question to get right. if i get it right i will pass this test. plz give me the right answer*
Answers: 2
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