For the given statement pn, write the statements p1, pk, and pk+1.
2 + 4 + 6 + . . + 2n = n(n+1)

=  2

= k(k+1)

= (k+1)(k+2)

Step-by-step explanation:

We are given the statement,

as 2 + 4 + 6 + . . . + 2n = n(n+1)

That is,

as 2 + 4 + 6 + . . . + 2n =

So, we have,

= = 2

= = 2 + 4 + 6 + . . . + 2k = k(k+1)

= = 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)

Thus, we get,

=  2

= k(k+1)

= (k+1)(k+2)

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3