The local theater is showing a matinee and offering a special deal for the community. a ticket for an adult costs $11 and a ticket for a child costs $6. the theater sells a total of 60 tickets and collects $460. *
how many adult tickets "x" and children tickets "y" are sold?

First, x+y=60 and solve for x

x= 60-y

Then set up the equation 11x+6y=460

Since, x=60-y, you plug in for y

11(60-y)+6y=460

660-11y+6y=460

660-5y=460

660-660-5y=460-660

-5y=-200

Divide both sides by 5 (you can drop the negative because they are both negative)

5y/5 = 200/5

y=40

Then take y & plug it back into the original equation of:

x+y = 60 (solve for x)

x+40=60

x+40-40=60-40

x=20

The answer is 20 adult tickets (x) and 40 child tickets (y) were sold.

6 (3) - 4 + 32

hope this

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b