What is the solution set of 2x^2 - 3x = 5?

{-1, -5/2}
{-1, 5/2}
{1, -5/2}

The answer is {-1, 5/2} and heres why:

The first step to solveing this equation is to set it to 0 like this Subtract 5 from both sides: 2x^2 -3x -5 =5 -5 then just Simplify: 2x^2 -3x -5 =0

Now to solve we must use a certain quadratic eqaution shown down below, because i have no other way to show my math better.

Now replace a with 2, b with -3, and c with -5. You then have to solve both for the postive equation and the negative equation.

If you would like even more detail just ask in the comments!

2

omg what happend to your question? if you could edit this question i can

step-by-step explanation: