Mathematics, 26.09.2019 10:50, Jasten
Not really understanding how the derivative of y=sin^2(x) is 2cosx*sinx? i know we use the chain rule, but steps would .
Answers: 1
![y=sin^2(x)\iff y=\left[ sin(x) \right]^2\impliedby \textit{pretty much} \\ \quad \\ \textit{now, using the chain-rule} \\ \quad \\ \cfrac{dy}{dx}=2[sin(x)]^1\cdot cos(x)\\ \quad \ \\ \quad \\ \textit{the cos(x), is the derivative of the inner function}](/tpl/images/0264/4843/7722a.png)
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Not really understanding how the derivative of y=sin^2(x) is 2cosx*sinx? i know we use the chain ru...
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