The lengths of three pieces of wire are in the ratio 10: 15: 8. if the length of the shortest piece of wire is 2.4 m, find the difference in the lengths of other two pieces of wire.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8