Systems of equations
2x+2y=16
2x+6y=28

2x+2y=16
2x+6y=28

all you have to do is subtract to get rid of the 2x and solve for y

2x+2y = 16
-2x-6y = -28

0 -4y = -12
y = 3

now we got y we can plug in or do the systems of equation again and find x.  lets do systems of equations again. 

2x+2y=16
2x+6y=28

this time i am going to multiple the top by -3  and then add the equations hopefully it is clear why I multiple by -3 

-3(2x+2y = 16)
2x +6y = 28 

-6x - 6y = -48
2x +6y = 28 

-4x + 0y = -20

x = 5 

 2x+2y=16
2x+6y=28we multiply one side negative sing 2x+2y=16
-2x-6y=-28
now add both equation 'x' will be gone
-4y=-12
each side divide by { -4 }
y=3now we get 'Y' then we looking for 'X' 
take 3 then blog in one of the orginal equation
2x+2(3)=16
now solve 'X' 
2x+6=16
number 6 move to the left side
2x=10
divide each side by 2
x=5
your answer is { Y=3 , X=5 } I THINK YOU UNDERSTAND WHAT I DID. GOOD LUCK