Answer asap if answered within 10 minutes i will give brainliest
i have already answered part a i only need with parts b & c
all numbered streets runs parallel to each other. both 3rd and 4th streets are intersected by king ave. as shown: (attached)
(b) suppose a car is traveling southwest on king avenue and turns left onto 3rd street. what is the measure of the angle created by the car's turning? explain your answer.
(c) suppose a car is traveling northeast on king avenue and turns right onto 3rd street. what is the measure of the angle created by the car's turning? explain your answer.

B. 75°

C. 105°

Step-by-step explanation:

We are given the figure of parallel lines with a line intersecting both of them as shown in the figure below.

B) We have, the car going south-west on King Avenue turns left onto 3rd street.

As, the lines representing 3rd street and 4th street are parallel. Their corresponding angles will be equal.

So, ∠1 = 75°

As, King Avenue intersects 3rd street, the vertical angles will be equal.

So, ∠2 = ∠1 = 75°

Thus, the angle made by the car's turning is 75°.

C) We have, the car going north-east on King Avenue turns right onto 3rd street.

As, the sum of angles on a straight line is 180°.

So, ∠2 + ∠3 = 180°

i.e. ∠3 = 180° - ∠2

i.e. ∠3 = 180° - 75°

i.e. ∠3 = 105°

Thus, the angle made by the car's turning is 105°.

FOR A

∠a+75°=180°

∠a=180°-75°

∠a=105°

FOR B

Angle b is the car's turn, 3rd and 4th street are parallel so the corresponding angles have equal measures so ∠b=75°.

FOR C

∠c+75°=180°

∠c=180°-75°

∠c=105°

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.