Find the area of a sector with a central angle of 32° and a radius of 8.5 millimeters. round to the nearest tenth.
a. 40.4 mm²
b. 2.4 mm²
c. 20.2 mm²
d. 9.5 mm²

360 degrees in a circle
32/360 of total area is sector area

area=pir^2
r=8.5
area=pi8.5^2
area=226.980022 mm^2
multiply it by 32/360
sector=20.17600195555556

round
sector=20.2

C is answer

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1. 0.3 •4 is the same as 4 groups of 0.32. 7•0.8 is the same as 7 groups of 0.83. it increases by 0.5 every time, so 0.5x4 it increases by 0.9 every time, so 0.9x5. 0.9•12=10.86. 0.47•5=2.35i can finish the next ones in a separate post