You want to create an id code for the students in your school based on three characters. the first and second characters must be a letter of the alphabet, and the third must be a digit between 1 and 9 inclusive. to find out how many different codes there are, would a list or tree diagram be practical in this case? why or why not?

As we know that there are 26 letters in a alphabet and we are asked to use 9 digits in the third place.

So, the total number of such cases possible are or the total number of codes than can be created using a letter in the first two place and a digit in the third place are:

     26×26×9=6084

( Since in the first place there are a choice of  26 letters and for the second place again we have a choice of 26 letters as it is not mentioned that the repetition is not allowed and for the third place we have 9 choices)

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation: