What equations best represents the problem? you drove for 425 miles at 60 mph. how long did it take you?

V = d / t  or  t = d / V

where

V = speed

d = distance

t = time

t = 7.08 hours

Step-by-step explanation:

In the field of Physics, the concept of "Speed" is defined as the vector magnitude - that is, it has a length and orientation - by means of which the distance traveled by an object or person in a time is expressed determined.

It is universally expressed with the capital letter V, while its measurement is usually measured in meters per second, based on the International System of Units. Likewise, it should be clarified that this measure should not be confused at any time with the Acceleration. To better explain this last point, it is necessary to clarify the speed refers to the rate of change of the position that a specific object has in a given unit of time, while acceleration refers to the rate of change experienced by the speed per unit of time.

If use the next equation:

t = d / V

t = ? is the incognita

d = 425 miles

V = 60 mph

So:

t = 425 miles / 60 mph

t = 7.08 hours

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

60%