Half of sarah's wire is equal to 2/5 of daniel's. chris has 3 times as much as sarah. in all, their wire measures 6 ft. how long is sarah's wire in feet?

Let x be the length of Daniel's wire. With the representation, Sarah's wire is 4x/5 and that of Chris is 3 time 4x/5. The equation that best represent the situation given above is,
                                       x + 4x/5 + 3(4x/5) = 6
The value of x in ft is 1.42. Therefore, Sarah's wire which is 4x/5 is approximately 1.14 ft long. 

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12