1. the width of a rectangle is 10 mm shorter than its length. its perimeter is 244 mm. let l equal the length of the rectangle.
a. write an expression for the width in terms of the length.
b. write an equation for the perimeter in terms of l.
c. solve the equation, clearly indicating the length of the rectangle.
d. solve for the width of the rectangle. clearly indicate the width of the rectangle.

Let l equal the length of the rectangle
width of a rectangle is 10 mm shorter than its length

a. Write an expression for the width in terms of the length?
 w = l - 10

b. Write an equation for the perimeter in terms of l. 
  P = l + l + (l-10) + (l-10)
  P =4l - 20

c. Solve the equation, clearly indicating the length of the rectangle.

   P =4l - 20
 244 = 4l - 20
4l = 244 + 20
4l = 264
l = 284/4
l = 66

d. Solve for the width of the rectangle. Clearly indicate the width of the rectangle.
w = l - 10
w = 66 - 10
w = 56

The density of the cube is 40