The number of houses in a town has been growing according to the recursive rule pn=pn-1 + 30, with initial population p0=200.

A) P1 = 230

P2 = 260

B) An explicit formula for Pn is; Pn = 200 + 30n

C) The prediction of number of houses in 10 years is; 500 houses

D) The number of years it will take for the number of houses to reach 400 is; 7 years.

We are given;

Pn = P_(n - 1) + 30

Initial population; P_0 = 200

A) Since Pn = P_(n - 1) + 30, then;

P1 = P_(1 - 1) + 30

P1 = P_0 + 30

P1 = 200 + 30

P1 = 230

Similarly;

P2 = P1 + 30

P2 = 230 + 30

P2 = 260

B) Since P1 = 230 and P2 = 260, then the difference between 2 consecutive terms is; d = 260 - 230

d = 30

Thus;

Explicit formula for Pn is;

Pn = P0 + nd

Pn = 200 + 30n

C) From B above, we saw that;

Pn = 200 + 30n

Thus;

Number of houses in ten years is;

P(10) = 200 + 30(10)

P(10) = 500 houses

D) If number of houses is 400. Then;

400 = 200 + 30n

30n = 400 - 200

30n = 200

n = 200/30

n ≈ 7 years

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The complete question is;

The number of houses in a town has been growing according to the recursive rule Pn = P_(n - 1) + 30, with initial population P_0 = 200

A. calculate P1 and P2

B. Find an explicit formula for Pn

C. Use your formula to predict the number of houses in 10 years.

D. When will the number of houses reach 400 houses?

For

For

To find the explicit formula, you need the first term and the difference which is 30. Then, we use the arithmetic sequence definition

For

In 10 years, the number of houses is 470.

For , we have to find

After 7.7 years, approximately, the number of houses will reach 400.

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question

c

step-by-step explanation:

i think because what else can be a sample of every member