Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting at point 1. draw ann's path. represent ann's walk with a vector of length 80 meters.

Ann walks 80 meters with a direction of 33° north of east starting. This corresponds to a vector of
r = 80 m and θ = 33°
You draw this by making a coordinate system, two lines perpendicular to each other with the intersection as the origin. Next, locate the ray that would correspond to the direction of 33° north of east. On that ray and starting from the origin, measure 80 m or use a scale.

Ibelieve it's a. 2.2 - x = -10.85 (plz tell me if it's right : ) )