Aconcession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. on friday night they sold a total of 300 hamburgers and hotdogs and made $420. how many of each did they sell?

what solution is reasonable?
question 3 options:

200 hamburgers and 50 hotdogs

50 hamburgers and 200 hotdogs

120 hamburgers and 180 hotdogs

100 hamburgers and 180 hotdogs

i think the answer is 120 hamburgers and 180 hotdogs ,but i'm not sure. to whoever me .

120 hamburgers and 180 hotdogs

Step-by-step explanation:

Let 'x' be the number of hamburgers and 'y' be the number of hotdogs sold.

Then, the total number of hamburgers and hotdogs sold on friday will be given by :_

On the basis of their cost, the total cost will be:-

Subtract (1) from (2), we get

Substitute the value of x in  (1), we get

Hence, they sold 120 hamburgers and 180 hotdogs.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: