The circle below is centered at the point (-1,2) and has a radius of length 3. what is its equation?

(x-h)²+(y-k)²=r²

when the center is (h,k) and the radius is r

given

(-1,2) and r=3

(x-(-1))²+(y-2)²=3²

(x+1)²+(y-2)²=3²

C is answer

Option C is correct.

Step-by-step explanation:

We have been given the center of circle: (-1,2) and radius of length 3.

The general equation of circle is:

Here, h= -1, k=2 and r=3

h and k is the center of circle

On substituting the values in the formula we get:

Therefore, Option C is correct.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation: