Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x minus three, over two, solve for f(g(x)) when x = 1.

Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x minus three, over two, solve for f(g(x)) when x = 1.

We want to evaluate f(g(1))

So g(x) = (x - 3)/2   and when x =1, g(1) = (1 - 3) /2 = -2/2 = -1

So f(g(1)) = f(-1) = (-1)^2 + 3(-1) + 6 =  1 - 3 + 6 = 4

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1

well the answer to that is xoxoxo

step-by-step explanation: