Mathematics

Mathematics, 12.10.2019 08:30, cheesy2271

3. now consider equations of the form x-a=sqrt (bx+c) where a, b, and c are all positive integers and b > 1
(a) create an equation of this form that has 7 as a solution and an extraneous solution. give the extraneous solution.
(b) what must be true about the value of bx+c to ensure that there is a real number solution to the equation? explain

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Mathematics, 19.09.2019 10:30, venegas122916

X+2= (square root) 3x+10 is of the form x+a = (square root) bx+c , where a, b, and c are all positive integers and . using this equation as a model, create your own equation that has extraneous solutions. (a) using trial and error with numbers for a, b, and c, create an equation of the form , where a, b, and c are all positive integers and such that 7 is a solution. (hint: substitute 7 for x, and choose a value for a. then square both sides so you can choose a, b, and c that will make the equation true.) (b) solve the equation you created in part 2a. (c) if your solution in part 2b did not have an extraneous solution, revise your equation so that 7 is one solution and there is an extraneous solution. if your solution in part 2b did have an extraneous solution, create another equation with different values of a, b, and c that also has 7 as one solution and an extraneous solution.

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Mathematics, 26.09.2019 05:30, 5001Je

2. the equation x+2= sqrt (3x+10) is of the form x+a=sqrt(bx+c) , where a, b, and c are all positive integers and b > 1. using this equation as a model, create your own equation that has extraneous solutions. (a) using trial and error with numbers for a, b, and c, create an equation of the form x+a=sqrt(bx+c) where a, b, and c are all positive integers and b > 1 such that 7 is a solution. (hint: substitute 7 for x, and choose a value for a. then square both sides so you can choose a, b, and c that will make the equation true.) (b) solve the equation you created in part 2a. (c) if your solution in part 2b did not have an extraneous solution, revise your equation so that 7 is one solution and there is an extraneous solution. if your solution in part 2b did have an extraneous solution, create another equation with different values of a, b, and c that also has 7 as one solution and an extraneous solution.

Answers: 1

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Mathematics, 25.10.2019 18:43, Jana1517

The equation x+2=sqrt(3x+10) is of the form , x+a=sqrt(bx+c),where a, b, and c are all positive integers and b> 1 . using this equation as a model, create your own equation that has extraneous solutions. using trial and error with numbers for a, b, and c, create an equation of the form x+a=sqrt(bx+c) , where a, b, and c are all positive integers and b> 1 such that 7 is a solution. (hint: substitute 7 for x, and choose a value for a. then square both sides so you can choose a, b, and c that will make the equation true.) solve the equation you created in part 2a. if your solution in part 2b did not have an extraneous solution, revise your equation so that 7 is one solution and there is an extraneous solution. if your solution in part 2b did have an extraneous solution, create another equation with different values of a, b, and c that also has 7 as one solution and an extraneous solution.

Answers: 1

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