What is ex(p), the value of the x-component of the electric field produced by q1 and q2 at point p? ?

You will have Ex(P)=(9E9)*(-3.9E-6)/(.067^2+.067^2). 
this will give you the magnitude of the electric field produced by q1. all thats left is to multiply your answer by a sin(45) and voila, there's your answer! 
This should be your final answer (-2764474.05 N/C) 

for the second part you do the same, use the formula but this time q2 will affect it because you are looking for the y-component. 

Ey(P)=(9E9)*(7.1E-6)/(.067^2) which equals out to 14234796.17 N/C. 
to get the final answer just use the answer from part A and subtract it from the above answer and you are all set to go!
This should be the final answer for the second part. (11470322.12 N/C) 

Cis your correct answer

What am i doing here. add?