One hour after a hiker left a camp, a cyclist set out to catch up. if the hiker traveled 3 miles per hour and the cyclist travelled 6 miles per hour faster, how long will it take the cyclist to catch up with the hiker?

0.5 hours it will take the cyclist to catch up with the hiker and this can be determined by equating the distance.

Given :

Let the total distance be 'd'. Let the time taken by the hiker to travel distance 'd' be 't' then the time taken by the cyclist is (t+1).

The speed of the hiker is 3 miles per hour and the speed of the cyclist is (6 + 3 = 9) 9 miles per hour.

The distance travel by both hiker and cyclist is 'd'.

Hiker Distance = Cyclist Distance

3(t  + 1) = 9t

3t + 3 = 9t

3 = 6t

t = 0.5 hour

0.5 hours it will take the cyclist to catch up with the hiker.

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